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	<title>Comments on: I want to use a capacitor for an alarm clock but am not completey sure on what size to use?</title>
	<atom:link href="http://www.batterybackupguide.com/blog/i-want-to-use-a-capacitor-for-an-alarm-clock-but-am-not-completey-sure-on-what-size-to-use/feed/" rel="self" type="application/rss+xml" />
	<link>http://www.batterybackupguide.com/blog/i-want-to-use-a-capacitor-for-an-alarm-clock-but-am-not-completey-sure-on-what-size-to-use/</link>
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	<pubDate>Thu, 17 May 2012 22:31:39 +0000</pubDate>
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		<title>By: pingerlee</title>
		<link>http://www.batterybackupguide.com/blog/i-want-to-use-a-capacitor-for-an-alarm-clock-but-am-not-completey-sure-on-what-size-to-use/comment-page-1/#comment-478</link>
		<dc:creator>pingerlee</dc:creator>
		<pubDate>Tue, 20 Jan 2009 01:02:15 +0000</pubDate>
		<guid isPermaLink="false">http://www.batterybackupguide.com/blog/i-want-to-use-a-capacitor-for-an-alarm-clock-but-am-not-completey-sure-on-what-size-to-use/#comment-478</guid>
		<description>well, charge in cap = voltage x value of cap, so value of cap = charge / voltage. You want the charge to last 3 sec, and charge = current x time, so cap value = (0.2Ax3sec)/10v=0.06F, which is a large cap. Remember  that you can use smaller caps in parallel if this is too large.</description>
		<content:encoded><![CDATA[<p>well, charge in cap = voltage x value of cap, so value of cap = charge / voltage. You want the charge to last 3 sec, and charge = current x time, so cap value = (0.2Ax3sec)/10v=0.06F, which is a large cap. Remember  that you can use smaller caps in parallel if this is too large.</p>
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		<title>By: some_yank</title>
		<link>http://www.batterybackupguide.com/blog/i-want-to-use-a-capacitor-for-an-alarm-clock-but-am-not-completey-sure-on-what-size-to-use/comment-page-1/#comment-477</link>
		<dc:creator>some_yank</dc:creator>
		<pubDate>Fri, 16 Jan 2009 18:11:40 +0000</pubDate>
		<guid isPermaLink="false">http://www.batterybackupguide.com/blog/i-want-to-use-a-capacitor-for-an-alarm-clock-but-am-not-completey-sure-on-what-size-to-use/#comment-477</guid>
		<description>Better check your math first.  If e= 120v and r = 50, you then have a 2.5 amp alarm clock....don't think so.  Once you know the true current consumption, you just need to calculate the capacitive time constant.</description>
		<content:encoded><![CDATA[<p>Better check your math first.  If e= 120v and r = 50, you then have a 2.5 amp alarm clock&#8230;.don&#8217;t think so.  Once you know the true current consumption, you just need to calculate the capacitive time constant.</p>
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		<title>By: oldguy</title>
		<link>http://www.batterybackupguide.com/blog/i-want-to-use-a-capacitor-for-an-alarm-clock-but-am-not-completey-sure-on-what-size-to-use/comment-page-1/#comment-476</link>
		<dc:creator>oldguy</dc:creator>
		<pubDate>Thu, 15 Jan 2009 14:00:48 +0000</pubDate>
		<guid isPermaLink="false">http://www.batterybackupguide.com/blog/i-want-to-use-a-capacitor-for-an-alarm-clock-but-am-not-completey-sure-on-what-size-to-use/#comment-476</guid>
		<description>use yor RC time constant formula to determine how long the cap's charge need to last to keep the clock powered and if a series resistor is needed to control the discharge</description>
		<content:encoded><![CDATA[<p>use yor RC time constant formula to determine how long the cap&#8217;s charge need to last to keep the clock powered and if a series resistor is needed to control the discharge</p>
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